Rfc2045 mime стандарта base64 python

How to convert a string to a base64 format standard RFC-2045 MIME?

No. This RFC is about the body of an email. Especially section «6.8. Base64 Content-Transfer-Encoding» is about the body, not the header of a message.

1 Answer 1

Base64 encoding in python: It provides encoding and decoding functions for the encodings specified in RFC 3548, which defines the Base16, Base32, and Base64 algorithms, and for the de-facto standard Ascii85 and Base85 encodings.

RFC-2045 MIME is used by email.

I think the solution you were looking for is a code for Base64 encoding with RFC 2045, check this:

# Copyright (C) 2002-2006 Python Software Foundation # Author: Ben Gertzfield # Contact: email-sig@python.org """Base64 content transfer encoding per RFCs 2045-2047. This module handles the content transfer encoding method defined in RFC 2045 to encode arbitrary 8-bit data using the three 8-bit bytes in four 7-bit characters encoding known as Base64. It is used in the MIME standards for email to attach images, audio, and text using some 8-bit character sets to messages. This module provides an interface to encode and decode both headers and bodies with Base64 encoding. RFC 2045 defines a method for including character set information in an `encoded-word' in a header. This method is commonly used for 8-bit real names in To:, From:, Cc:, etc. fields, as well as Subject: lines. This module does not do the line wrapping or end-of-line character conversion necessary for proper internationalized headers; it only does dumb encoding and decoding. To deal with the various line wrapping issues, use the email.Header module. """ __all__ = [ 'base64_len', 'body_decode', 'body_encode', 'decode', 'decodestring', 'encode', 'encodestring', 'header_encode', ] from binascii import b2a_base64, a2b_base64 from email.utils import fix_eols CRLF = '\r\n' NL = '\n' EMPTYSTRING = '' # See also Charset.py MISC_LEN = 7 # Helpers def base64_len(s): """Return the length of s when it is encoded with base64.""" groups_of_3, leftover = divmod(len(s), 3) # 4 bytes out for each 3 bytes (or nonzero fraction thereof) in. # Thanks, Tim! n = groups_of_3 * 4 if leftover: n += 4 return n def header_encode(header, charset='iso-8859-1', keep_eols=False, maxlinelen=76, eol=NL): """Encode a single header line with Base64 encoding in a given charset. Defined in RFC 2045, this Base64 encoding is identical to normal Base64 encoding, except that each line must be intelligently wrapped (respecting the Base64 encoding), and subsequent lines must start with a space. charset names the character set to use to encode the header. It defaults to iso-8859-1. End-of-line characters (\\r, \\n, \\r\\n) will be automatically converted to the canonical email line separator \\r\\n unless the keep_eols parameter is True (the default is False). Each line of the header will be terminated in the value of eol, which defaults to "\\n". Set this to "\\r\\n" if you are using the result of this function directly in email. The resulting string will be in the form: "=?charset?b?WW/5ciBtYXp66XLrIHf8eiBhIGhhbXBzdGHuciBBIFlv+XIgbWF6euly?=\\n =?charset?b?6yB3/HogYSBoYW1wc3Rh7nIgQkMgWW/5ciBtYXp66XLrIHf8eiBhIGhh?=" with each line wrapped at, at most, maxlinelen characters (defaults to 76 characters). """ # Return empty headers unchanged if not header: return header if not keep_eols: header = fix_eols(header) # Base64 encode each line, in encoded chunks no greater than maxlinelen in # length, after the RFC chrome is added in. base64ed = [] max_encoded = maxlinelen - len(charset) - MISC_LEN max_unencoded = max_encoded * 3 // 4 for i in range(0, len(header), max_unencoded): base64ed.append(b2a_base64(header[i:i+max_unencoded])) # Now add the RFC chrome to each encoded chunk lines = [] for line in base64ed: # Ignore the last character of each line if it is a newline if line.endswith(NL): line = line[:-1] # Add the chrome lines.append('=?%s?b?%s?=' % (charset, line)) # Glue the lines together and return it. BAW: should we be able to # specify the leading whitespace in the joiner? joiner = eol + ' ' return joiner.join(lines) def encode(s, binary=True, maxlinelen=76, eol=NL): """Encode a string with base64. Each line will be wrapped at, at most, maxlinelen characters (defaults to 76 characters). If binary is False, end-of-line characters will be converted to the canonical email end-of-line sequence \\r\\n. Otherwise they will be left verbatim (this is the default). Each line of encoded text will end with eol, which defaults to "\\n". Set this to "\r\n" if you will be using the result of this function directly in an email. """ if not s: return s if not binary: s = fix_eols(s) encvec = [] max_unencoded = maxlinelen * 3 // 4 for i in range(0, len(s), max_unencoded): # BAW: should encode() inherit b2a_base64()'s dubious behavior in # adding a newline to the encoded string? enc = b2a_base64(s[i:i + max_unencoded]) if enc.endswith(NL) and eol != NL: enc = enc[:-1] + eol encvec.append(enc) return EMPTYSTRING.join(encvec) # For convenience and backwards compatibility w/ standard base64 module body_encode = encode encodestring = encode def decode(s, convert_eols=None): """Decode a raw base64 string. If convert_eols is set to a string value, all canonical email linefeeds, e.g. "\\r\\n", in the decoded text will be converted to the value of convert_eols. os.linesep is a good choice for convert_eols if you are decoding a text attachment. This function does not parse a full MIME header value encoded with base64 (like =?iso-8895-1?b?bmloISBuaWgh?=) -- please use the high level email.Header class for that functionality. """ if not s: return s dec = a2b_base64(s) if convert_eols: return dec.replace(CRLF, convert_eols) return dec # For convenience and backwards compatibility w/ standard base64 module body_decode = decode decodestring = decode 

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Python — How to Decode a RFC2045 Base64 String

Could not find a way to decode a RFC2045 format base64 string I am trying to decode a RFC2045 format base64 string inn Python 3 but just could not find a way to achieve the same result as org.apache.commons.codec.binary.Base64.decodeBase64 . Here is the Java code:

import static org.apache.commons.codec.binary.Base64.decodeBase64; String str1 = "j-FH-F9__CIiwyg0o3A2mKflRBnxZSMwktDJQyvRevc"; byte[] b1 = decodeBase64(str1); System.out.println(b1.length + " " + b1); 
import base64 from email import base64mime def bytes2list(bdata): return [b if b < 128 else b - 256 for b in bdata] b64str = 'j-FH-F9__CIiwyg0o3A2mKflRBnxZSMwktDJQyvRevc' b64str += " mt24 mb12">
    javapythonbase64apache-commons
)" data-controller="se-share-sheet" data-se-share-sheet-title="Share a link to this question" data-se-share-sheet-subtitle="" data-se-share-sheet-post-type="question" data-se-share-sheet-social="facebook twitter devto" data-se-share-sheet-location="1" data-se-share-sheet-license-url="https%3a%2f%2fcreativecommons.org%2flicenses%2fby-sa%2f4.0%2f" data-se-share-sheet-license-name="CC BY-SA 4.0" data-s-popover-placement="bottom-start">Share
)">edited Mar 26, 2019 at 0:32
asked Mar 25, 2019 at 14:17
5
    str1 = 'j-. ' is not valid in Java andjshell> Base64.getDecoder().decode("j-FH-F9__CIiwyg0o3A2mKflRBnxZSMwktDJQyvRevc") | Exception java.lang.IllegalArgumentException: Illegal base64 character 2d (minus is not valid Base64)
    – user85421
    Mar 25, 2019 at 14:42
    being more lenient: jshell> Base64.getMimeDecoder().decode("j-FH-F9__CIiwyg0o3A2mKflRBnxZSMwktDJQyvRevc") ==> byte[29] - consider using the decoder that comes with Java.
    – user85421
    Mar 25, 2019 at 14:47
    I used Groovy to run the Java code. Sorry missed the single vs double quote issue
    – hanaZ
    Mar 26, 2019 at 0:24
    The data was encoded with RFC 2045 and only the Apache common decoded it right. Need to do the same thing with Python 3
    – hanaZ
    Mar 26, 2019 at 0:32
    1
    The data was not encoded per RFC 2045. It was encoded per RFC 4648 section 5, using the "URL and Filename Safe Alphabet" with '-' and '_' in place of the usual '+' and '/' characters. To decode this data in Python, use the urlsafe_b64decode method of the base64 module.
    – ottomeister
    Mar 26, 2019 at 0:42
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Found the answer in How to decode base64 url in python?. The code should be:

b1 = base64.urlsafe_b64decode(b64str)

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