Python get path without filename

Get file path without file name

I have had a lot of trouble in the past trying to use file paths without preceding them with ‘r’, so I’m not sure of the best way to handle the incomplete file name. Question: Let’s say I opened a file called file1.mp3 in a PyQt5 app using the file dialog and assigned it to a variable like this: How can I get the file name instead of a file path so I can display it in a statusBar?

Get file path without file name

fullpath = '/path/to/some/file.jpg' filepath = '/'.join(fullpath.split('/')[:-1]) 

But I think it is open to errors

dirname, fname = os.path.split(fullpath) 

Split the pathname path into a pair, (head, tail) where tail is the last pathname component and head is everything leading up to that. The tail part will never contain a slash; if path ends in a slash, tail will be empty. If there is no slash in path , head will be empty.

os.path is always the module suitable for the platform that the code is running on.

fullpath = '/path/to/some/file.jpg' import os os.path.dirname(fullpath) 

Using pathlib you can get the path without the file name using the .parent attribute:

from pathlib import Path fullpath = Path("/path/to/some/file.jpg") filepath = str(fullpath.parent) # /path/to/some/ 

This handles both UNIX and Windows paths correctly.

fullpath = '/path/to/some/file.jpg' index = fullpath.rfind('/') fullpath[0:index] 

Getting file path from command line argument in python, Starting with python 3.4 you can use argparse together with pathlib: import argparse from pathlib import Path parser = argparse.ArgumentParser () parser.add_argument («file_path», type=Path) p = parser.parse_args () print (p.file_path, type (p.file_path), p.file_path.exists ()) I think the most elegant way …

Get absolute path of file without filename using Python pathlib

I want to replace file_location = os.path.abspath(os.path.dirname(__file__)) with pathlib to get the aboslute path of the file without the filename
with using directorypath = pathlib.Path(__file__).resolve() gives me the absolute path + the filename
how can I get the absolute path without the filename ?

You can use ‘.parent’: directorypath = pathlib.Path(__file__).resolve().parent
Path.parent

Get Path of the Current File in Python, To get the current working directory, we can use the getcwd () function that returns the current directory path. We can pass this path to the dirname () function to get the directory. For example: import os print(os.path.abspath(os.getcwd())) Output: C:\Sample\Python. Write for us.

Opening file from path without knowing full file name (python)

I am trying to open a file using the full path, but I don’t know the complete name of the file, just a unique string within it.

i = identifier doc = open(r'C:\my\path\**.txt'.format(i), 'r') 

Now obviously this doesn’t work because I’m trying to use the wildcard along with the raw string. I have had a lot of trouble in the past trying to use file paths without preceding them with ‘r’, so I’m not sure of the best way to handle the incomplete file name. Should I just forget raw string notation and use ‘\\\\’ for the file path?

From the question comments:

import glob import os i = "identifier" basePath = r"C:\my\path" filePaths = glob.glob(os.path.join(basePath,'**.txt'.format(i))) # Just open first ocurrence, if any if filePaths: print "Found: ", filePaths[0] doc = open(filePaths[0], 'r') 

import os def foo(path): _, _, files = next(os.walk(path)) print(files) files = foo(r'C:\Users') files[1] 

Python — How to get filename using os.path.basename, You need to use filedialog.askopenfilename instead of filedialog.askopenfile to obtain the filename without side effects (like opening a file). This returns the full path; you can extract the filename from the fullpath using os.path.basename. import os import tkinter as tk from tkinter import filedialog …

Get file name from an opened file, not a file path

Let’s say I opened a file called file1.mp3 in a PyQt5 app using the file dialog and assigned it to a variable like this:

song = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song[0]) url = QUrl.fromLocalFile(song[0]) self.playlist.addMedia(QMediaContent(url)) 

How can I get the file name instead of a file path so I can display it in a statusBar? Or even better, is there a «now playing»-like function I could use or create?

There are several simple ways to get the name of a file:

song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song) url = QUrl.fromLocalFile(song) self.playlist.addMedia(QMediaContent(url)) your_statusbar.showMessage("now playing <>".format(url.fileName())) 

song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song) url = QUrl.fromLocalFile(song) self.playlist.addMedia(QMediaContent(url)) filename = QFileInfo(song).fileName() your_statusbar.showMessage("now playing <>".format(filename)) 

song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song) url = QUrl.fromLocalFile(song) self.playlist.addMedia(QMediaContent(url)) from pathlib import Path filename = Path(song).name your_statusbar.showMessage("now playing <>".format(filename)) 

song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song) url = QUrl.fromLocalFile(song) self.playlist.addMedia(QMediaContent(url)) import os filename = song.rstrip(os.sep) your_statusbar.showMessage("now playing <>".format(filename)) 

song, _ = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)") print(song) url = QUrl.fromLocalFile(song) self.playlist.addMedia(QMediaContent(url)) import os _ , filename = os.path.split(os.sep) your_statusbar.showMessage("now playing <>".format(filename)) 

Self-explanatory. You just need to slice the string. And because you are learning, I’ll slice it the wrong way, for you to find out why.

filepath = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")[0] filename = filepath.split("/")[-1] print(filename) 

After that you can simply use

self..showMessage("Now playing song or whatever".format(filename)) 

However, that will only work on «some» systems. If you want to use that application on a different computer, you should first normalize the path (some systems use // and others \ for folders) and then you slice it with a safe built-in command.

import os # Careful with this library, Read the documentation first filepath = os.path.normpath(filepath) # Normalize it filename = filepath.split(os.sep) # Slice it 

The entire code should work like this:

import os filepath = QFileDialog.getOpenFileName(self, "Open Song", "~", "Sound Files (*.mp3 *.ogg *.wav *.m4a)")[0] print(filepath) filepath = os.path.normpath(filepath) song = filepath.split(os.sep) url = QUrl.fromLocalFile(filepath) self.playlist.addMedia(QMediaContent(url)) self..showMessage("Now playing song or whatever and it was at folder".format(song, filepath)) 

programming is not magic, you have a file path i.e: c://myfolder/song.mp3 — assuming your music files are named after the song, you must parse the url for the song name and set the status bar title/label to the song you are currently playing. I suggest you take a entry lvl course on python before mixing qt frameworks into it.

Python — how can I get filenames without directory name, os.path.basename:. Return the base name of pathname path.This is the second element of the pair returned by passing path to the function split().Note that the result of this function is different from the Unix basename program; where basename for ‘/foo/bar/’ returns ‘bar’, the basename() function returns an empty …

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Get Path To File Without Filename Python With Code Examples

Hello everybody, on this submit we’ll have a look at learn how to resolve Get Path To File Without Filename Python in programming.

import os filepath="/a/path/to/my/file.txt" os.path.dirname(filepath) # Yields '/a/path/to/my'

By investigating quite a lot of use situations, we have been capable of reveal learn how to resolve the Get Path To File Without Filename Python downside that was current.

How do you take away a filename from a path in Python?

os. take away() methodology in Python is used to take away or delete a file path.26-Jul-2022

How do I separate the filename and path in Python?

cut up() methodology in Python is used to Split the trail title right into a pair head and tail. Here, tail is the final path title element and head is every little thing main as much as that. In the above instance ‘file. txt’ element of path title is tail and ‘/dwelling/User/Desktop/’ is head.21-Oct-2019

How do I get the listing of a file in Python?

In order to acquire the Current Working Directory in Python, use the os. getcwd() methodology. This operate of the Python OS module returns the string containing absolutely the path to the present working listing.14-Jul-2022

How do I get filenames with out an extension in Python?

Get filename from the trail with out extension utilizing rsplit() Python String rsplit() methodology returns a listing of strings after breaking the given string from the correct facet by the desired separator.14-Sept-2022

How do I delete a filename from path?

The methodology fileCompinent() is used to take away the trail info from a filename and return solely its file element. This methodology requires a single parameter i.e. the file title and it returns the file element solely of the file title.30-Jul-2019

What is __ file __ Python?

The __file__ variable: __file__ is a variable that accommodates the trail to the module that’s at the moment being imported. Python creates a __file__ variable for itself when it’s about to import a module.08-Aug-2021

How do I get simply the filename in Python?

Python Program to Get the File Name From the File Path

• import os # file title with extension file_name = os.path.basename(‘/root/file.ext’) # file title with out extension print(os.path.splitext(file_name)[0]) Run Code.
• import os print(os.path.splitext(file_name))
• from pathlib import Path print(Path(‘/root/file.ext’).stem)

How do you cut up paths?

The Split-Path cmdlet returns solely the desired a part of a path, such because the mother or father folder, a subfolder, or a file title. It also can get objects which are referenced by the cut up path and inform whether or not the trail is relative or absolute. You can use this cmdlet to get or submit solely a particular a part of a path.

How do you utilize absolute path in Python?

Use abspath() to Get the Absolute Path in Python path property. To get absolutely the path utilizing this module, name path. abspath() with the given path to get absolutely the path. The output of the abspath() operate will return a string worth of absolutely the path relative to the present working listing.10-Feb-2021

How do I get the trail of a file?

Click the Start button after which click on Computer, click on to open the situation of the specified file, maintain down the Shift key and right-click the file. Copy As Path: Click this feature to stick the total file path right into a doc. Properties: Click this feature to instantly view the total file path (location).23-Jul-2019

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