Python add datetime and time

Pressing the Red Button

Using the built-in modules datetime and timedelta, you can perform date and time addition/subtraction in python:

from datetime import datetime from datetime import timedelta #Add 1 day print datetime.now() + timedelta(days=1) #Subtract 60 seconds print datetime.now() - timedelta(seconds=60) #Add 2 years print datetime.now() + timedelta(days=730) #Other Parameters you can pass in to timedelta: # days, seconds, microseconds, # milliseconds, minutes, hours, weeks #Pass multiple parameters (1 day and 5 minutes) print datetime.now() + timedelta(days=1,minutes=5)

Here is a python reference that gives more examples and advanced features:
http://docs.python.org/library/datetime.html

If you are coming from a .net or sql environment, here are the above examples in C# and SQL (Microsoft) for comparison:
C#

DateTime myTime = new DateTime(); --Add 1 day myTime.AddDays(1); --Subtract 60 seconds myTime.AddSeconds(-60); --Add 2 years myTime.AddYears(2);

--Add 1 day select DATEADD(day, 1, getdate()) --Subtract 60 seconds select DATEADD(second, -60, getdate()) --Add 2 years select DATEADD(Year, 2, getdate())

2 Responses to “Adding Dates and Times in Python”

Brian Hansen Says:
January 26th, 2012 at 1:05 pm Pretty useless examples unless you’re actually doing some string conversion too.

Tysonm Says:
September 17th, 2012 at 10:20 pm Great post, I believe blog owners should larn a lot from this website its really user friendly. So much good information on here :D.

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Pressing the Red Button

Using the built-in modules datetime and timedelta, you can perform date and time addition/subtraction in python:

from datetime import datetime from datetime import timedelta #Add 1 day print datetime.now() + timedelta(days=1) #Subtract 60 seconds print datetime.now() - timedelta(seconds=60) #Add 2 years print datetime.now() + timedelta(days=730) #Other Parameters you can pass in to timedelta: # days, seconds, microseconds, # milliseconds, minutes, hours, weeks #Pass multiple parameters (1 day and 5 minutes) print datetime.now() + timedelta(days=1,minutes=5)

Here is a python reference that gives more examples and advanced features:
http://docs.python.org/library/datetime.html

If you are coming from a .net or sql environment, here are the above examples in C# and SQL (Microsoft) for comparison:
C#

DateTime myTime = new DateTime(); --Add 1 day myTime.AddDays(1); --Subtract 60 seconds myTime.AddSeconds(-60); --Add 2 years myTime.AddYears(2);

--Add 1 day select DATEADD(day, 1, getdate()) --Subtract 60 seconds select DATEADD(second, -60, getdate()) --Add 2 years select DATEADD(Year, 2, getdate())

2 Responses to “Adding Dates and Times in Python”

Brian Hansen Says:
January 26th, 2012 at 1:05 pm Pretty useless examples unless you’re actually doing some string conversion too.

Tysonm Says:
September 17th, 2012 at 10:20 pm Great post, I believe blog owners should larn a lot from this website its really user friendly. So much good information on here :D.

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Python add datetime and time

Last updated: Feb 19, 2023
Reading time · 3 min

# Add hours to datetime in Python

Use the timedelta() class from the datetime module to add hours to datetime, e.g. result = dt + timedelta(hours=10) .

The timedelta class can be passed a hours argument and adds the specified number of hours to the datetime.

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from datetime import datetime, timedelta d = '2023-11-24 09:30:00.000123' # 👇️ convert string to datetime object dt = datetime.strptime(d, '%Y-%m-%d %H:%M:%S.%f') print(dt) # 👉️ 2023-11-24 09:30:00.000123 result = dt + timedelta(hours=3) print(result) # 👉️ 2023-11-24 12:30:00.000123 

Make sure to import the datetime and timedelta classes from the datetime module.

The example creates a datetime object from a datetime string and adds hours to it.

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from datetime import datetime, timedelta d = '2023-11-24 09:30:00.000123' # 👇️ convert string to datetime object dt = datetime.strptime(d, '%Y-%m-%d %H:%M:%S.%f') print(dt) # 👉️ 2023-11-24 09:30:00.000123 result_1 = dt + timedelta(hours=3) print(result_1) # 👉️ 2023-11-24 12:30:00.000123 

The datetime.strptime() method returns a datetime object that corresponds to the provided date string, parsed according to the format.

If you have a date string that is formatted in a different way, use this table of the docs to look up the format codes you should pass as the second argument to the strptime() method.

# Using the datetime class to create a datetime object

The following example uses the datetime class to create a datetime object and the timedelta class to add hours to it.

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from datetime import datetime, timedelta dt = datetime(2023, 9, 24, 9, 30, 35) print(dt) # 👉️ 2023-09-24 09:30:35 result = dt + timedelta(hours=4) print(result) # 👉️ 2023-09-24 13:30:35 

We passed values for the year , month , day , hour , minute and seconds arguments.

# Adding hours to the current time

If you need to add hours to the current time, use the datetime.today() method to get a datetime object that stores the current time.

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from datetime import datetime, timedelta # ✅ add hours to current time now = datetime.today() print(now) # 👉️ 2023-02-19 05:40:02.239652 result = now + timedelta(hours=5) print(result) # 👉️ 2023-02-19 10:40:02.239652 

The datetime.today() method returns the current local datetime.

We need to use a datetime object because it automatically rolls over the days, months and years if necessary.

This wouldn’t be possible if we only had the time component. For example, 11:59:30PM + 2 hours would raise an exception.

# Only extracting the time component after adding hours

If you only need to extract the time after the operation, call the time() method on the datetime object.

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from datetime import datetime, timedelta now = datetime.now() print(now) # 👉️ 2023-02-19 05:41:07.814924 result = now + timedelta(hours=5) print(result) # 👉️ 2023-02-19 10:41:07.814924 # ✅ only get updated time print(result.time()) # 👉️ 10:41:07.814924 

The datetime.time method returns a time object with the same hour, minute, second and millisecond.

# Formatting the time as HH:MM:SS after adding hours

If you need to get the time formatted as HH:MM:SS , use a formatted string literal.

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from datetime import datetime, timedelta now = datetime.now() print(now) # 👉️ 2023-02-19 05:41:40.114944 result = now + timedelta(hours=3) print(result) # 👉️ 2023-02-19 08:41:40.114944 print(result.time()) # 👉️ 08:41:40.114944 # 👇️ format as HH:MM:SS print(f'result:%H:%M:%S>') # 👉️ 08:41:40 

Formatted string literals (f-strings) let us include expressions inside of a string by prefixing the string with f .

Make sure to wrap expressions in curly braces — .

Formatted string literals also enable us to use the format specification mini-language in expression blocks.

# Adding hours to a time using datetime.combine()

If you only have the time component, use the datetime.combine method to combine the time with the current (or some other) date and get a datetime object.

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from datetime import datetime, date, timedelta, time t = time(6, 25) print(t) # 👉️ 06:25:00 result = datetime.combine(date.today(), t) + timedelta(hours=6) print(result) # 👉️ 2023-02-19 12:25:00 only_t = result.time() print(only_t) # 👉️ 12:25:00 

The datetime.combine method takes a date and time as arguments and returns a new datetime object by combining them.

Once we get a datetime object, we can use the timedelta class to add hours to it.

# Additional Resources

You can learn more about the related topics by checking out the following tutorials:

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