Php test if file uploaded

Php how to test if file has been uploaded completely

Get a list of all currently opened files in that directory by parsing the output of the UNIX/Linux command and check if the file you’re checking is in that list (take Nasir’s comment from above into account if you encounter permission problems). Find out if your has a that for example gives uncompleted files the extension «.part» or locks the file on the file system level (like vsftp).

Php how to test if file has been uploaded completely

Is there any way to check if file has been uploaded completely on the server? My scenario: User uploads file over ftp and my other PHP task is running in cronjob. Now I would like to check if file has been uploaded or if user is still uploading. It is essential because then I know if I can work with that file or wait until it is uploaded. Thank you.

If you have control over the application doing the upload, you can require that it upload the file to name.tmp , and when it’s done uploading rename it to name.final . Your PHP script could look only for *.final names.

I had the same scenario and found a quick solution that worked for me:

While a file is uploading via FTP, the value of filemtime($yourfile) is continuously modified. When time() minus filemtime($yourfile) is more than X , uploading has stopped. In my scenario, 30 was a good value for x, you might want to use any diferent value, but it should usefully be at least 3.

I do know that this method doesn’t guarantee the file’s integrity, but, as no one but me is going to upload, i dare to assume that.

if you are running php on linux then lsof can help you

$output = array(); exec("lsof | grep file/path/and/name.ext",$output); if (count($output)) < echo 'file in use'; >else

EDIT: in case of permission issue. by using sudo or suid methods php script can get required permissions to execute lsof command . to set suid you have to issue following command as root.

su root chmod u+s /usr/sbin/lsof 

There are many different ways to solve this. Just to name a few:

1. Use a signal file that is created before the upload and removed when it’s completed.
2. Find out if your FTP server has a configuration option that for example gives uncompleted files the extension «.part» or locks the file on the file system level (like vsftp).
3. Get a list of all currently opened files in that directory by parsing the output of the UNIX/Linux lsof command and check if the file you’re checking is in that list (take Nasir’s comment from above into account if you encounter permission problems).
4. Check if the last modification of that file is longer ago than a specific threshold.

As it seems your users can use any FTP client they want, the first method (signal file) can’t be used. The second and third answers need a deeper understanding of UNIX/Linux and are system dependend.

So I think that method #4 is the way to go in PHP as long as processing latency (depending on the configured threshold) is no problem. It is straightforward and doesn’t depend on any external commands:

// Threshold in seconds at which uploads are considered to be done. $threshold = 300; // Using the recursive iterator lets us check subdirectories too // (as this is FTP anything is possible). Its also quite fast even for // big directories. $it = new \RecursiveIteratorIterator(new \RecursiveDirectoryIterator($uploadDir); while($it->valid()) < // Ignore ".", ".." and other directories. Just recursively check all files. if (!$it->isDot() && !$it->isDir()) < // $it->key() is the current file name we are checking. // Just check if it's last modification was more than $threshold seconds ago. if (time() - filemtime($it->key() > $threshold)) < printf("Upload of file \"%s\" finished\n", $it->key()); // Your processing goes here. // Don't forget to move the file out so that it's not identified as // just being completed everytime this script runs. You might also mark // it in any way you like as being complete if you don't want to move it. > > $it->next(); > 

I hope this helps anyone having this problem.

Verify whether ftp is complete or not?

PHP: How do I avoid reading partial files that are pushed to me with FTP?

I need know how much bytes has been uploaded for, I need know where I can get how much bytes has been uploaded. File.length is the total size. android progress-bar http-post android-asynctask. Share. Improve this question. Follow edited Mar 6, 2018 at 10:49. CopsOnRoad. 179k 55 55 gold badges 549 549 silver badges 387 387 bronze badges.

How to know if an image has been uploaded or not?

do you know if is there a method to know if the image has been uploaded?

I mean, i have a Foo_Class, and this class can have an attached image, but its presence is not necessary. Is there a way to know if a particular instance of that class have the image or not?

If foo.image? returns true, then file uploaded.

When you added Paperclip to your model you added paperclip specific rows, mine are

cover_file_name cover_content_type cover_file_size cover_updated_at 

Then I check whether it is nil or not

 Foo_Class.cover_file_name.nil? 

I think that the proper solution is to use the file? method.

using exists? will do a request to the server to check if the file is there, which can be quite slow, especially if it’s on a different server or on S3.

using foo.image_file_name.nil? is probably the same as file? under the covers, but ou don’t want to dependant on the implementation of paperclip, which could someday change.

If this is in my model

has_attached_file :avatar, :styles => "230x50>", :card_image => "180x50>"> 

You can check if the image is uploaded for a user i.e @user

This will return boolean value.

Word choice — «Upload to» vs. «upload on», 1 Answer. Sorted by: 19. Generally you «upload to» and «download from». You might express that you «uploaded from your laptop to your server», which uses both from and to. You might say that you «can do the upload on that machine in the corner», but that refers to the machine you performed the command to …

Shiny: Show buttons only after file has been uploaded

I’m experimenting with Shiny and I love it. I built a little application where students upload a csv file and then choose a dependent variables and in dependent variable s and then R computes a linear regression. It works fine. I have it uploaded at:

[You can use this file to test it if you want. «beer» is the dependent variable and the rest of the variables except «id» are the independent]

# server.R library(shiny) shinyServer(function(input, output) < filedata read.csv(infile$datapath) >) output$dependent ) output$independents ) output$contents ) >) >) 

# ui.R library(shiny) shinyUI(fluidPage( titlePanel("Multiple Linear Regression"), sidebarLayout( sidebarPanel( fileInput('file1', 'Choose CSV File', accept=c('text/csv', 'text/comma-separated-values,text/plain', '.csv')), tags$hr(), uiOutput("dependent"), uiOutput("independents"), tags$hr(), actionButton("action", "Press after reading file and selecting variables") ), mainPanel( verbatimTextOutput('contents') ) ) )) 

My question is: I want to make the appearance of the button «Press After reading file and selecting variables » conditional on a succesful uploading.

I have tried to use the suggestion contained here:

Make conditionalpanel depend on files uploaded with fileInput

But I just can’t make it work.

Here’s the working ShinyApp and the final version of both ui.R and server.R based on all the suggestions provided by Marat.

# ui.R library(shiny) shinyUI(fluidPage( titlePanel("Multiple Linear Regression with R/Shiny"), sidebarLayout( sidebarPanel( p("Please upload a CSV formatted file with your data."), fileInput('file1', label='Click button below to select the file in your computer.', accept=c('text/csv', 'text/comma-separated-values,text/plain', '.csv')), tags$hr(), uiOutput("dependent"), uiOutput("independents"), tags$hr(), uiOutput('ui.action') # instead of conditionalPanel ), mainPanel( p("Here's the output from your regression:"), verbatimTextOutput('contents') ) ) )) 

# server.R library(shiny) shinyServer(function(input, output) < filedata read.csv(infile$datapath) >) output$ui.action ) output$dependent ) output$independents ) output$contents ) >) >) 

Once again thanks for your help Marat.

 # ui.R library(shiny) shinyUI(fluidPage( titlePanel("Multiple Linear Regression"), sidebarLayout( sidebarPanel( fileInput('file1', 'Choose CSV File', accept=c('text/csv', 'text/comma-separated-values,text/plain', '.csv')), tags$hr(), uiOutput("dependent"), uiOutput("independents"), tags$hr(), uiOutput('ui.action') # instead of conditionalPanel ), mainPanel( verbatimTextOutput('contents') ) ) )) 

# server.R library(shiny) shinyServer(function(input, output) < filedata read.csv(infile$datapath) >) output$dependent ) output$independents ) output$contents ) >) output$ui.action ) >) 

Php how to test if file has been uploaded completely, Get a list of all currently opened files in that directory by parsing the output of the UNIX/Linux lsof command and check if the file you’re checking is in that list (take Nasir’s comment from above into account if you encounter permission problems). Check if the last modification of that file is longer ago than a specific threshold. Code sample$filename = ‘somefile.txt’;if (file_exists($filename)) Feedback

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PHP is_uploaded_file() Function

Check whether the specified filename is uploaded via HTTP POST:

$file = «test.txt»;
if(is_uploaded_file($file)) echo («$file is uploaded via HTTP POST»);
> else echo («$file is not uploaded via HTTP POST»);
>
?>

The output of the code above could be:

Definition and Usage

The is_uploaded_file() function checks whether the specified file is uploaded via HTTP POST.

Syntax

Parameter Values

Technical Details

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is_uploaded_file

Возвращает TRUE , если файл filename был загружен при помощи HTTP POST. Это полезно для удостоверения того, что злонамеренный пользователь не пытается обмануть скрипт так, чтобы он работал с файлами, с которыми работать не должен — к примеру, /etc/passwd .

Такие проверки особенно полезны, если существует вероятность того, что операции над файлом могут показать его содержимое пользователю или даже другим пользователям той же системы.

Для правильной работы, функции is_uploaded_file() нужен аргумент вида $_FILES[‘userfile’][‘tmp_name’] , — имя закачиваемого файла на клиентской машине $_FILES[‘userfile’][‘name’] не подходит.

Список параметров

Возвращаемые значения

Возвращает TRUE в случае успешного завершения или FALSE в случае возникновения ошибки.

Примеры

Пример #1 Пример использования функции is_uploaded_file()

if ( is_uploaded_file ( $_FILES [ ‘userfile’ ][ ‘tmp_name’ ])) echo «Файл » . $_FILES [ ‘userfile’ ][ ‘name’ ] . » успешно загружен.\n» ;
echo «Отображаем содержимое\n» ;
readfile ( $_FILES [ ‘userfile’ ][ ‘tmp_name’ ]);
> else echo «Возможная атака с участием загрузки файла: » ;
echo «файл ‘» . $_FILES [ ‘userfile’ ][ ‘tmp_name’ ] . «‘.» ;
>

Смотрите также

• move_uploaded_file() — Перемещает загруженный файл в новое место
• $_FILES
• Простой пример использования можно найти в разделе «Загрузка файлов на сервер».

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