Float object has no attribute split python

Float object has no attribute split python

minutes = [] seconds = [] for i in range (len (df ["time"]) ―― 1): a_time = df ["time"] [i] .split (":") minute = int (a_time [0]) second = float (a_time [1]) minutes.append (minute) seconds.append (second)

-------------------------------------------------- ------------------------- AttributeError Traceback (most recent call last) in 3 for i in range (len (df ["time"]) ―― 1): 4 a_time = [] ---->5 a_time = df ["time"] [i] .split (":") 6 minute = int (a_time [0]) 7 second = float (a_time [1]) AttributeError:'float' object has no attribute'split'

I get an error like this.
Why?
I would appreciate it if you could answer.

You said that there is no such thing as a split in a float object.
Find out what’s in df [«time»] [i].

Related articles

• python — the generated object will be cut off in 10 seconds
• python — speech processing typeerror:’int’ object is not subscriptable
• python — ‘numpyndarray’ object has no attribute’numpy’ error
• python — ‘httpresponse’ object has no attribute’cookies’
• python — typeerror:’list’ object is not callable
• python — [opencv] i want to display the area of ​​each object at the position adjacent to the object
• python — about unhashable, object is not callable
• how to solve equations in python
• python — object is not displayed in html in django queryset
• python — i want to solve this problem
• [python] i don’t know how to solve the error
• python — i want to store an object in an array
• python — beautifulsoup gives error’nonetype’ object has no attribute’text’
• typeerror in python:’str’ object is not callable
• python — i want to solve the problem that i get the error typeerror: xxxxxxxx takes no arguments
• python 3x — about the amount of data for object detection using machine learning
• python — attributeerror:’series’ object has no attribute’flags’ error
• the following issues were raised in python 3, but i can’t solve them
• python — how to solve errors when learning with svm
• python — i want to distribute video in object storage with access restrictions fw uses flask i want to use flask as a proxy, but

Источник

Float object has no attribute split python

Last updated: Jan 29, 2023
Reading time · 3 min

# AttributeError: ‘float’ object has no attribute ‘X’ (Python)

The Python «AttributeError: ‘float’ object has no attribute» occurs when we try to access an attribute that doesn’t exist on a floating-point number, e.g. 5.4 .

To solve the error, make sure the value is of the expected type before accessing the attribute.

# Calling split() on a floating-point number

Here is an example of how the error occurs.

Copied! 
example = 5.4 print(type(example)) # 👉️ # ⛔️ AttributeError: 'float' object has no attribute 'split' result = example.split('.') print(result) 

We tried to call the split() method on a floating-point number and got the error.

If you print() the value you are accessing the attribute on, it will be a float.

To solve the error, you need to track down where exactly you are setting the value to a float in your code and correct the assignment.

To solve the error in the example, we have to convert the floating-point number to a string to be able to access the string-specific split() method.

Copied! 
example = 5.4 result = str(example).split('.') print(result) # 👉️ ['5', '4'] 

# Calling round() on a floating-point number

Another common cause of the error is calling a round() method on a float.

Copied! 
example = 3.6 # ⛔️ AttributeError: 'float' object has no attribute 'round' result = example.round() 

To solve the error, we have to pass the float as an argument to the round() function, not call the function on the float.

Copied! 
example = 5.4 result = round(example) print(result) # 👉️ 5 

Instead of accessing the round() function on the float, e.g. example.round() , we have to pass the floating point number as an argument to the round() function.

The round function takes the following 2 parameters:

Name	Description
number	the number to round to ndigits precision after the decimal
ndigits	the number of digits after the decimal the number should have after the operation (optional)

The round function returns the number rounded to ndigits precision after the decimal point.

If ndigits is omitted, the function returns the nearest integer.

Instead of accessing the round() function on the float, e.g. my_float.round() , we have to pass the floating point number as an argument to the round() function, e.g. round(3.5) .

# Check if an object contains an attribute

If you need to check whether an object contains an attribute, use the hasattr function.

Copied! 
example = 5.4 if hasattr(example, 'round'): print(example.round) else: print('Attribute is not present on object') # 👉️ this runs 

The hasattr function takes the following 2 parameters:

Name	Description
object	The object we want to test for the existence of the attribute
name	The name of the attribute to check for in the object

The hasattr() function returns True if the string is the name of one of the object’s attributes, otherwise False is returned.

Using the hasattr function would handle the error if the attribute doesn’t exist on the object, however, you still have to figure out where the variable gets assigned a float value in your code.

# Figure out where the variable got assigned a floating-point number

A good way to start debugging is to print(dir(your_object)) and see what attributes the object has.

Here is an example of what printing the attributes of a float looks like.

Copied! 
example = 5.4 # [. 'as_integer_ratio', 'conjugate', 'fromhex', 'hex', 'imag', 'is_integer', 'real', . ] print(dir(example)) 

If you pass a class to the dir() function, it returns a list of names of the class’s attributes, and recursively of the attributes of its bases.

If you try to access any attribute that is not in this list, you would get the error.

To solve the error, either convert the value to the correct type before accessing the attribute, or correct the type of the value you are assigning to the variable before accessing any attributes.

I wrote a book in which I share everything I know about how to become a better, more efficient programmer.

Источник

Attributeerror: float object has no attribute split [SOLVED]

In this article, we will show you how to solve the error attributeerror: float object has no attribute split in Python. What does this error indicate, and why does it occur? If you have that thought, read through the end of this article to find the answer.

The error “ attributeerror: float object has no attribute split ” is an error in Python that occurs when we attempt to use the split() method on a floating-point number object.

The split() method cannot be used on a floating-point number object because float objects lack the “split” attribute, which leads to this error when we attempt to use it.

Before we begin our tutorial, have a quick overview of Python and AttributeError.

What is Python?

Python is one of the most popular programming languages. It is used for developing a wide range of applications. It is a high-level programming language that is usually used by developers nowadays due to its flexibility.

What is AttributeError?

An attributeerror is an error that appears in our Python codes when we try to access an attribute of a non-existent object. In addition, this occurs when we attempt to perform non-supported operations.

Now that we understand this error and even what Python and an AttributeError are, let’s move on to our “how to fix this error” tutorial.

How to solve “float object has no attribute split” in Python

The solution we will show you might or might not work for you, but here it is:

To solve the error attributeerror: float object has no attribute split in Python, convert the float object to a string object before calling the split() method.

Example code that could result in this problem:

Traceback (most recent call last): File "C:\Users\pies-pc1\PycharmProjects\pythonProject\main.py", line 2, in split_x = x.split('.') ^^^^^^^ AttributeError: 'float' object has no attribute 'split'

Here’s an example with the correct code:

x = 3.14 x_string = str(x) split_x = x_string.split('.')

By using this code, the error will be gone.

What are the causes of the error to occur?

1. Using the split() method on a floating-point number object. As mentioned above, you cannot use the split() method on a floating-point number object because float objects lack the “split” attribute.

1. The function argument type is not correct. For example, if you give a floating-point number as input to a function that expects a string and that function then uses the split() method on the number, you’ll get an error.

1. The data type conversion is not correct. Be careful when converting a floating-point number to a string using the str() function.

1. Typos. You might also get this kind of error due to typos.

Conclusion

In conclusion, the Python error attributeerror: ‘float’ object has no attribute ‘split’ can be easily solved by converting the float object to a string object before calling the split() method.

By following the guide above, there’s no doubt that you’ll be able to resolve this error quickly and without a hassle.

I think that’s all for today, ITSOURCECODERS! We hope you’ve learned a lot from this. If you have any questions or suggestions, please leave a comment below, and for more attributeerror tutorials in Python, visit our website.

Leave a Comment Cancel reply

You must be logged in to post a comment.

Источник

Как решить ошибку атрибута объект float не имеет атрибута split в Python?

Когда я запускаю приведенный ниже код, появляется сообщение об ошибке атрибута: объект float не имеет атрибута split в python.

Хотелось бы узнать, почему возникает эта ошибка.

def text_processing(df): """""=== Lower case == = """ '''First step is to transform comments into lower case''' df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words)) return df df = text_processing(df) 

Полная трассировка ошибки:

Traceback (most recent call last): File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1664, in main() File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1658, in main globals = debugger.run(setup['file'], None, None, is_module) File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1068, in run pydev_imports.execfile(file, globals, locals) # execute the script File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile exec(compile(contents+"\n", file, 'exec'), glob, loc) File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 53, in df = text_processing(df) File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in text_processing df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words)) File "C:\Users\L31307\AppData\Roaming\Python\Python37\site-packages\pandas\core\series.py", line 3194, in apply mapped = lib.map_infer(values, f, convert=convert_dtype) File "pandas/_libs/src\inference.pyx", line 1472, in pandas._libs.lib.map_infer File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words)) AttributeError: 'float' object has no attribute 'split' 

Вы вообще поняли, почему у вас возникла ошибка? Независимо от того, какой у вас фрейм данных, его значения относятся к типу float . Но вы вызываете для них строковую функцию split . Как вы ожидаете, что это будет работать? Либо преобразуйте свой столбец, либо сделайте проверку, чтобы разделение пропускало столбцы с типом float.

Сообщение об ошибке означает, что столбец df[‘content’] содержит float , которые не могут быть split .

У меня такая же ошибка, и после удаления нулевых значений или значений nan с помощью df.dropna(inplace=True) указанная выше ошибка больше не существует.

Источник