Find int length java

Determining the length of an integer number in Java

Syntax: The method’s syntax is as follows. Parameters: The parameters are described in detail. There are various ways to determine the number of digits in a number: — Create a custom method that takes an input and repeatedly divides it by 10 until the number becomes 0. — Utilize mathematical properties. — Convert the number to a string and use string methods. Solution 3: If you wish to determine the length of a number, MChaker’s solution is the correct one.

How to count the number of digits in an int value? [duplicate]

Transform the numerical value into a String format and determine its length.

int length = String.valueOf(eg[i]).length(); 

int length = Integer.valueOf(eg[i]).toString().length(); 

Employ this mathematical formula under the condition that all the values stored in the array are exclusively positive numbers.

int length = (int)(Math.log10(eg[i])+1); 

The object eg[i] belongs to the category int , but it lacks the length attribute.

Numerous methods exist to determine the number of digits in a given number: «»».

• Create your own function that takes in a int and repeatedly divides it by 10 until the value becomes zero.

• using math properties:

  int length = (int) (Math.log10(number) + 1);

• Utilizing the methods of the converted String representation of the number.

If you are interested in determining the length of a number, MChaker’s solution is the correct choice. However, if you want to determine whether a number consists of a single digit or multiple digits, you may want to consider the alternative solution below:

public class NumberTest < public static void main(String[] args) < int[] eg = ; System.out.println("Array Length: " + eg.length); for(int i=0; i < eg.length; i++) < System.out.println("#" + i + ": Value: " + eg[i] + " one digit number: " + isOneDigitNumber(eg[i])); >> static private boolean isOneDigitNumber(int number)

This is the output of the code mentioned earlier.

Array Length: 8 #0: Value: 21 one digit number: false #1: Value: 20 one digit number: false #2: Value: 1 one digit number: true #3: Value: 12 one digit number: false #4: Value: 2 one digit number: true #5: Value: -3 one digit number: true #6: Value: -8 one digit number: true #7: Value: -20 one digit number: false #7: Value: -20 one digit number: false 

Java String length() Method with Examples, The Java String length() method is a method that is applicable for string objects. length() method returns the number of characters present in

Java display length of int containing leading zeros

Due to the precision provided by @DavidConrad and @DrewKennedy, int number = 0123 is considered equivalent to int number = 83 because 0123 serves as a constant of type octal .

If you desire to retain the initial 0 , declare it as a String instead.

String number = "0123"; int length = number.length(); 

Subsequently, when the number is required, just use the code Integer.parseInt(number) .

What is the reason for the syntax of octal representation being 0xx in Java?

The syntax of Java was intentionally made similar to that of C, as shown on page 20 of the keynote presentation by James Gosling at the JVM Languages Summit 2008 (20_Gosling_keynote.pdf).

This is how octal constants are defined in the C language.

When an integer constant starts with 0x or 0X, it is considered hexadecimal. If it starts with the digit 0, it is octal. Otherwise, it is assumed to be decimal.

Please be aware that this section is a copy and paste from the response provided by @gnat on programmers.stackexchange.

Refer to this link for insights on the rationale behind the syntax of octal notation in Java: https://softwareengineering.stackexchange.com/questions/221797/reasoning-behind-the-syntax-of-octal-notation-in-java.

String number = "0123"; int length = number.length(); // equals 4 

The internal representation of 0123 is identical to 123, so using an int will not work. The program does not retain the formatting of the value, only the actual value itself.

One option is to initialize a string.

String number = "0123"; int numberLengthWithLeadingZeroes = number.length(); // == 4 int numberValue = Integer.parseInt(number); // == 123 

Java Program to Count Number of Digits in an Integer, Example 1: Count Number of Digits in an Integer using while loop · After the first iteration, num will be divided by 10 and its value will be 345. · After the

Java — String length() Method

Description

The length of the string is determined by the number of 16-bit Unicode characters it contains.

Syntax

Here is the syntax of this method −

Parameters

Here is the detail of parameters −

Return Value

Example

import java.io.*; public class Test < public static void main(String args[]) < String Str1 = new String("Welcome to Tutorialspoint.com"); String Str2 = new String("Tutorials" ); System.out.print("String Length :" ); System.out.println(Str1.length()); System.out.print("String Length :" ); System.out.println(Str2.length()); >>

The outcome generated will be as follows −

Output

String Length :29 String Length :9

How to get length of integer in java Code Example, int x = 1234; int lengthOfInt = String.valueOf(x).length(); //convert integer to String //and get length of the String.

List size() method in Java with Examples

The list interface in java utilizes the size() method to retrieve the count of elements present in this list container.

The method does not require any parameters.

The return value of this method is the count of elements present in the list.

Let’s consider a list of integers as an illustration.

Input : Output : 5

Java

// Java program to Illustrate size() method // of List class for Integer value // Importing required classes import java.util.*; // Main class public class GFG < // Main driver method public static void main(String[] arg) < // Creating object of ArrayList class Listlist = new ArrayList(); // Populating List by adding integer elements // using add() method list.add( 1 ); list.add( 2 ); list.add( 3 ); list.add( 4 ); list.add( 5 ); // Printing elements of List System.out.println( "Before operation: " + list); // Getting total size of list // using size() method int size = list.size(); // Printing the size of List System.out.println( "Size of list = " + size); > >

Before operation: [1, 2, 3, 4, 5] Size of list = 5

Java

// Java program to Illustrate size() method // of List class for Integer value // Importing required classes import java.util.*; // Main class public class GFG < // Main driver method public static void main(String[] args) < // Creating an empty string list by // declaring elements of string type Listlist = new ArrayList(); // Populating List by adding string elements // using add() method list.add( "Geeks" ); list.add( "for" ); list.add( "Geeks" ); // Printing the List System.out.println( "Before operation: " + list); // Getting total size of list // using size() method int size = list.size(); // Printing the size of list System.out.println( "Size of list = " + size); > >

Before operation: [Geeks, for, Geeks] Size of list = 3

Java — String length() Method, This method returns the length of this string. The length is equal to the number of 16-bit Unicode characters in the string. Syntax. Here is the syntax of this

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How to find length of integer in Java

We can find the length of the integer in many ways. The length of an integer is defined as the count of the number of digits for the given integer.

These are the approaches for finding the length of an integer in Java:

• By using the while loop
• By using the String
• By using the Continuous Multiplication
• By using the Logarithm
• By using the Recursion method

1. By using the while loop

The variable n contains the user-inputted integer. Once the test phrase n!= 0 is converted to 0, the while loop iterates until it returns 0. (false).

• The count is increased by one after the initial iteration, bringing the value of n to 354.
• The number n would be 35 in the second iteration, and the count will have increased by 2.
• The number n will be 3 just after the third iteration, and the count is increased by 3.
• The loop is ended when n reaches 0 at the beginning of the fourth iteration.
• The loop then ends when the test expression is determined to be false.

The application of the abovementioned strategy is seen below:

IntegerExample.java

//this program is for finding the number of digits in a given integer //import section import Java.io.*; import Java.util.*; public class IntegerExample < // method for finding the number of digits in the given integer public int countDigits(int number) < int c = 0; while(number!= 0) < //the last of the given integer is removed for counting the digits number = number/ 10; // the value of count(c) is updated to +1 c = c + 1; >return c; > // main section of the program public static void main(String argvs[]) < // the array consisting of integers as an input int array[] = ; //finding the length of the array int length = array.length; // an object (object) is created for the class IntegerExample IntegerExample object = new IntegerExample(); for(int i = 0; i < length; i++) < int c = object.countDigits(array[i]); System.out.println("The number of digits in the given number "+array[i]+" is--"+c); >> > 

2. By using the String

Another method is making the integer into a string after calculating its length. The string’s size determines the size of the string. The very same is seen in the program which follows.

IntegerStringExample.java

//this program is for finding the number of digits in a given integer //import section import Java.io.*; import Java.util.*; public class IntegerStringExample < //method for finding the number of digits in the given integer public int countDigits(int n) < // the given integer is converted to a string String s = Integer.toString(n); // computing the size of the string int len = s.length(); return len; >// main section of the program public static void main(String argvs[]) < // the array consisting of integers as an input int array[] = ; //finding the length of the array int length = array.length; // an object (object) is created for the class IntegerExample IntegerStringExample object = new IntegerStringExample(); for(int i = 0; i < length; i++) < int c = object.countDigits(array[i]); System.out.println("The number of digits in the given number "+array[i]+" is: "+c); >> > 

3. By using the Continuous Multiplication

A number 1 can be multiplied by 10 until it exceeds the value of n. When multiplying by 10, we add one to a variable, counting for each time. The count’s final value indicates the length of the integer num. Now let us study it with the support of the following Java program.

IntegerMultiplicationExample.java

//This program is for finding the length of the integer in Java //by using the continuous multiplication method //import section //class IntegerMultiplicationExample is created public class IntegerMultiplicationExample < //method for determining the length of the integer public int countDigits(int num) < int temporary = 1; int c = 0; while(temporary // the value of c will contain the total number //of the digits in the given integer number return c; > // main section of the program public static void main(String argvs[]) < // user input array int array[] = ; // the total elements of the array can be calculated using the length function int len = array.length; // IntegerMultiplicationExample obj = new IntegerMultiplicationExample(); for(int i = 0; i < len; i++) < int c = obj.countDigits(array[i]); System.out.println("The number digits in " + array[i] + " is " + c); >> > 

4. By using the Logarithm

Log can also be used to find the integer’s length in Java. The program below can be used to understand how can find the integer’s length using the log function.

IntegerLogExample3.java

//This program is for finding the length of the integer in Java //by using the log function in the math module method //import section public class IntegerLogExample3 < // public int countDigits(int number) < // method for determining the length of the integer int length = (int) (Math.log10(number) + 1); // the length of the integer can be returned return length; >// main section public static void main(String argvs[]) < //the array given by the user as user input int array[] = ; // the length of the user input array can be calculated using the length int len = array.length; //an object ob for the class IntegerLogExample3 is created IntegerLogExample3 ob = new IntegerLogExample3(); for(int i = 0; i < len; i++) < int c = ob.countDigits(array[i]); System.out.println("The number of digits in " + array[i] + " is " + c); >> > 

5. By using the Recursion method

Recursion is the process in which a function can be called by itself until it has reached a certain condition. For every function call, the allocation of the memory can be done. The concept of recursion in Java can determine the number of the digits in the given integer.

IntegerLengthRecursionExample4.java

//This program is for finding the length of the integer in Java //by using the concept of recursion //import section public class IntegerLengthRecursionExample4 < // the method count can be used as the Digits in the given integer public int countDigits(int number) < // the base case is checked using the if the condition if(number/ 10 == 0) < return 1; >// by the process of recursion, the method can be called // from the opposite direction, increment the length return 1 + countDigits(number/ 10); > // main section of the program public static void main(String argvs[]) < // int array[] = ; // the length of the integer can be calculated using the length function int len = array.length; // an object ob is created for the class IntegerLengthRecursionExample4 ob = new IntegerLengthRecursionExample4 (); for(int i = 0; i < len; i++) < int c = ob.countDigits(array[i]); System.out.println("The number of digits in " + array[i] + " is " + c); >> > 

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Calculate Length of Integer in Java

1. Use the for Loop to Calculate the Length of an Integer in Java
2. Use the Math.log10() Function to Calculate the Length of an Integer in Java
3. Use the toString() Function to Calculate the Length of an Integer in Java

In this tutorial, we calculate the number of digits in an integer in Java.

Use the for Loop to Calculate the Length of an Integer in Java

First, we will see a simple iterative solution for this. We will divide the integer by 10, storing the count in each iteration until the number equals zero.

The below code demonstrates the above method.

public class Digits   static int count_digit(int x)    int count = 0;  while (x != 0)   x = x / 10;  ++count;  >  return count;  >  public static void main(String[] args)    int x = 345;  System.out.print(count_digit(x));  > > 

We can also implement the above logic using a divide and conquer with recursion.

Use the Math.log10() Function to Calculate the Length of an Integer in Java

Now let’s see the log-based solution for this. We will be using the logarithm of base 10 for counting the number of the digits in an integer. This method will work only on positive integers. We will be importing the java.util class from which we will use the Math.log10() function.

import java.util.*;  public class Digits    static int count_digit(int x)    return (int)Math.floor(Math.log10(x) + 1);  >   public static void main(String[] args)    int x = 345;  System.out.print(count_digit(x));  > > 

Use the toString() Function to Calculate the Length of an Integer in Java

Another method is to change the integer into a string and then calculate its length. We will use the toString() function from the java.util package to convert the integer to a string. The length() method returns the length of the string.

The below code demonstrate the above code.

import java.util.*; public class Digits   static void count_digits(int x)    String dig = Integer.toString(x);  System.out.println(+dig.length());  >  public static void main(String args[])    int x = 345;  count_digits(x);  > > 

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